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fix(challenges): update consecutive-numbers
A little bit harder by having as input consecutive numbers needed to consider
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@ -22,3 +22,4 @@ coverage
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# misc
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.DS_Store
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temp
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tmp
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@ -4,26 +4,42 @@ Created by [@Divlo](https://github.com/Divlo) on 28 June 2021.
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## Instructions
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Write a function which takes a list of integers, and which returns the (possibly empty) list of pairs of successive consecutive integers that there may be in the list.
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Write a function which takes a list of integers, and which returns the list of of successive consecutive integers that there may be in the list.
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### Input
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```txt
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7
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1
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2
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5
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3
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4
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```
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### Output
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```txt
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1, 2
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3, 4
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```
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First input, is the number of consecutive numbers needed to consider it as "consecutive", the second input is the list of integers.
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## Examples
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See the `test` folder for examples of input/output.
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### Example 1
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#### Input
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```txt
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2
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5 ; 1 ; 2 ; 3 ; 8 ; -5 ; -4 ; 7
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```
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#### Output
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```txt
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1 ; 2
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2 ; 3
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-5 ; -4
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```
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### Example 2
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#### Input
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```txt
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3
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5 ; 1 ; 2 ; 3 ; 8 ; -5 ; -4 ; 7
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```
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#### Output
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```txt
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1 ; 2 ; 3
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```
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@ -6,21 +6,28 @@ for value in sys.stdin:
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input_values.append(value.rstrip('\n'))
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def consecutive_numbers(numbers: List[int]) -> List[List[int]]:
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consecutive_numbers_pairs: List[List[int]] = []
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def consecutive_numbers(numbers: List[int], couple_length: int) -> List[List[int]]:
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result: List[List[int]] = []
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numbers_length = len(numbers)
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for index in range(numbers_length):
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number = numbers[index]
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is_last_number = index == numbers_length - 1
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if not is_last_number and number + 1 == numbers[index + 1]:
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consecutive_numbers_pairs.append([number, number + 1])
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return consecutive_numbers_pairs
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consecutive: List[int] = [numbers[index]]
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for couple_index in range(1, couple_length, 1):
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is_last_number = index + couple_index == numbers_length
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if is_last_number:
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break
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if (numbers[index] + couple_index == numbers[index + couple_index]):
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consecutive.append(numbers[index] + couple_index)
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is_consecutive = len(consecutive) == couple_length
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if is_consecutive:
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result.append(consecutive)
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return result
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numbers: List[int] = []
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for value in input_values:
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for value in input_values[1].split(' ; '):
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numbers.append(int(value))
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consecutive_numbers_pairs = consecutive_numbers(numbers)
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for pairs in consecutive_numbers_pairs:
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print(f"{pairs[0]} ; {pairs[1]}")
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result = consecutive_numbers(numbers, int(input_values[0]))
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for consecutive in result:
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consecutive = [str(number) for number in consecutive]
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print(' ; '.join(consecutive))
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@ -1,6 +1,2 @@
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7
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1
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2
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5
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3
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4
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7 ; 1 ; 2 ; 5 ; 3 ; 4
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@ -0,0 +1,2 @@
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2
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1 ; 4 ; 3 ; 5
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@ -1,4 +1,2 @@
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1
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4
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3
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5
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2
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1 ; 4 ; 5 ; 3
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@ -0,0 +1 @@
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4 ; 5
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@ -1,4 +1,2 @@
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1
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4
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5
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3
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2
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5 ; 1 ; 2 ; 3 ; 8 ; -5 ; -4 ; 7
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@ -1 +1,3 @@
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4 ; 5
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1 ; 2
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2 ; 3
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-5 ; -4
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@ -1,8 +1,2 @@
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5
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1
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2
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3
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8
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-5
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-4
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7
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5 ; 1 ; 2 ; 3 ; 8 ; -5 ; -4 ; 7
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@ -1,3 +1 @@
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1 ; 2
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2 ; 3
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-5 ; -4
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1 ; 2 ; 3
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2
challenges/consecutive-numbers/test/6/input.txt
Normal file
2
challenges/consecutive-numbers/test/6/input.txt
Normal file
@ -0,0 +1,2 @@
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3
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5 ; 1 ; 2 ; 3 ; 4 ; 5 ; -4 ; 7
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3
challenges/consecutive-numbers/test/6/output.txt
Normal file
3
challenges/consecutive-numbers/test/6/output.txt
Normal file
@ -0,0 +1,3 @@
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1 ; 2 ; 3
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2 ; 3 ; 4
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3 ; 4 ; 5
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